What are the solutions to the equation 2x^2-11x+14=0 ?

The solutions to the equation 2x^2-11x+14=0 are x= 7/2 ,x=2

Find the zeros of 2x^2-11x+14=0

The zeros of 2x^2-11x+14=0 are x= 7/2 ,x=2

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2 x^{2} - 11 x + 14 = 0

x = \frac{7}{2}, x = 2

Solution steps

2 x^{2} - 11 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 \cdot 14 = 3

x_{1, 2} = \frac{- ( - 11 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 3}{2 \cdot 2}

x = \frac{- ( - 11 ) + 3}{2 \cdot 2} : \frac{7}{2}

x = \frac{- ( - 11 ) - 3}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = 2

\frac{- 3}{- 6 i}

7 (2 x - 4) = 42

\frac{8 ! 2 !}{6 ! 4 !}

m^{2} - 144 = 0

\frac{2 ^{2}}{2 ^{2}}

What are the solutions to the equation 2x^2-11x+14=0 ?
The solutions to the equation 2x^2-11x+14=0 are x= 7/2 ,x=2
Find the zeros of 2x^2-11x+14=0
The zeros of 2x^2-11x+14=0 are x= 7/2 ,x=2