What are the solutions to the equation m^2+2m-3=0 ?

The solutions to the equation m^2+2m-3=0 are m=1,m=-3

Find the zeros of m^2+2m-3=0

The zeros of m^2+2m-3=0 are m=1,m=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 2 m - 3 = 0

m = 1, m = - 3

Solution steps

m^{2} + 2 m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 3) = 4

m_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 4}{2 \cdot 1}, m_{2} = \frac{- 2 - 4}{2 \cdot 1}

m = \frac{- 2 + 4}{2 \cdot 1} : 1

m = \frac{- 2 - 4}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

m = 1, m = - 3

\frac{π}{8} + \frac{π}{4}

4^{\frac{1}{6}}

x (x - 2) \leq 24

192

(2 \frac{1}{2})^{2}

What are the solutions to the equation m^2+2m-3=0 ?
The solutions to the equation m^2+2m-3=0 are m=1,m=-3
Find the zeros of m^2+2m-3=0
The zeros of m^2+2m-3=0 are m=1,m=-3