What is factor 40x^2-17x-12 ?

The solution to factor 40x^2-17x-12 is (8x+3)(5x-4)

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factor 40x^2-17x-12

factor

40 x^{2} - 17 x - 12

(8 x + 3) (5 x - 4)

Solution steps

40 x^{2} - 17 x - 12

Break the expression into groups

= (40 x^{2} + 15 x) + (- 32 x - 12)

Factor out

5 x

from

40 x^{2} + 15 x : 5 x (8 x + 3)

Factor out

- 4

from

- 32 x - 12 : - 4 (8 x + 3)

= 5 x (8 x + 3) - 4 (8 x + 3)

Factor out common term

8 x + 3

= (8 x + 3) (5 x - 4)

x^{2} - 8 x + 16

c^{2} - 18 c + 81

(5 y + 2) (y - 3) = - 12 (2 + y)

- 22 + 3 h = 7 (6 h + 5)

\frac{x ^{2} - 4}{x} > 0

What is factor 40x^2-17x-12 ?
The solution to factor 40x^2-17x-12 is (8x+3)(5x-4)