What is y+5>=-6\land 7y<35 ?

The solution to y+5>=-6\land 7y<35 is -11<= y<5

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y+5>=-6\land 7y<35

y + 5 \geq - 6 and 7 y < 35

- 11 \leq y < 5

Interval Notation

[- 11, 5)

Solution steps

y + 5 \geq - 6 and 7 y < 35

y + 5 \geq - 6 : y \geq - 11

7 y < 35 : y < 5

Combine the intervals

y \geq - 11 and y < 5

Merge Overlapping Intervals

- 11 \leq y < 5

(- \frac{2}{3})^{- 3}

\frac{( \frac{5}{2} )}{4}

4 + 6 i

2 x (x + 12)^{2} - x^{3} (x + 12)

x^{2} - 6 x - 10 = 0