What are the solutions to the equation a^2-2a=8 ?

The solutions to the equation a^2-2a=8 are a=4,a=-2

Find the zeros of a^2-2a=8

The zeros of a^2-2a=8 are a=4,a=-2

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a^{2} - 2 a = 8

a = 4, a = - 2

Solution steps

a^{2} - 2 a = 8

Move

8

to the left side

a^{2} - 2 a - 8 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 8) = 6

a_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 1}, a_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 1}

a = \frac{- ( - 2 ) + 6}{2 \cdot 1} : 4

a = \frac{- ( - 2 ) - 6}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

a = 4, a = - 2

\frac{1}{x ^{2} - 1} - \frac{2}{( x + 1 ) ^{2}}

\frac{25 - a ^{2}}{3 a - 15}

15 x^{2} - 25 x - 10

1098

9 - 3 i

What are the solutions to the equation a^2-2a=8 ?
The solutions to the equation a^2-2a=8 are a=4,a=-2
Find the zeros of a^2-2a=8
The zeros of a^2-2a=8 are a=4,a=-2