What are the solutions to the equation 4x^2-48x+72=0 ?

The solutions to the equation 4x^2-48x+72=0 are x=3(2+sqrt(2)),x=3(2-sqrt(2))

Find the zeros of 4x^2-48x+72=0

The zeros of 4x^2-48x+72=0 are x=3(2+sqrt(2)),x=3(2-sqrt(2))

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4 x^{2} - 48 x + 72 = 0

x = 3 (2 + 2), x = 3 (2 - 2)

Decimal Notation

x = 10.24264 \dots, x = 1.75735 \dots

Solution steps

4 x^{2} - 48 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 4 \cdot 72}{2 \cdot 4}

(- 48)^{2} - 4 \cdot 4 \cdot 72 = 242

x_{1, 2} = \frac{- ( - 48 ) \pm 24 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 24 2}{2 \cdot 4}, x_{2} = \frac{- ( - 48 ) - 24 2}{2 \cdot 4}

x = \frac{- ( - 48 ) + 24 2}{2 \cdot 4} : 3 (2 + 2)

x = \frac{- ( - 48 ) - 24 2}{2 \cdot 4} : 3 (2 - 2)

The solutions to the quadratic equation are:

x = 3 (2 + 2), x = 3 (2 - 2)

\frac{3}{16} = (- \frac{5}{4}) + g

9 - (x + 2) < 0

1 < 6 x + 7 < 25

\frac{- 10}{x - 5} \geq \frac{- 11}{x - 6}

12 x + 48 y

What are the solutions to the equation 4x^2-48x+72=0 ?
The solutions to the equation 4x^2-48x+72=0 are x=3(2+sqrt(2)),x=3(2-sqrt(2))
Find the zeros of 4x^2-48x+72=0
The zeros of 4x^2-48x+72=0 are x=3(2+sqrt(2)),x=3(2-sqrt(2))