What is ((x-9)(x+1))/(x-2)>= 0 ?

The solution to ((x-9)(x+1))/(x-2)>= 0 is -1 = 9

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((x-9)(x+1))/(x-2)>= 0

\frac{( x - 9 ) ( x + 1 )}{x - 2} \geq 0

- 1 \leq x < 2 or x \geq 9

Interval Notation

[- 1, 2) \cup [9, \infty)

Solution steps

\frac{( x - 9 ) ( x + 1 )}{x - 2} \geq 0

Identify the intervals

- 1 \leq x < 2 or x \geq 9

2 (\frac{7}{25})^{2} - 1

(- 8 k + 1) (- 8 k + 1)

2 t^{2} + 11 t + 5

x - 9 > - 6

- (\frac{5}{2})^{0}

What is ((x-9)(x+1))/(x-2)>= 0 ?
The solution to ((x-9)(x+1))/(x-2)>= 0 is -1<= x<2\lor x>= 9