What is 1/(ln(2))ln|2^x+9|>0.999 ?

The solution to 1/(ln(2))ln|2^x+9|>0.999 is True for all x

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1/(ln(2))ln|2^x+9|>0.999

\frac{1}{ln ( 2 )} ln ∣ 2^{x} + 9 ∣ > 0.999

True for all x

Interval Notation

(- \infty, \infty)

Solution steps

\frac{1}{ln ( 2 )} ln ∣ 2^{x} + 9 ∣ > 0.999

Find positive and negative intervals

- \infty < x < \infty

Solve the inequality for each interval

True for all x

1 - (- \frac{13}{85})^{2}

2 x^{2} + 15 x + 28

6 x - 30 = 84

9 x^{2} + 7 = 12 x

(- 2 x + 3)^{2} = 49

What is 1/(ln(2))ln|2^x+9|>0.999 ?
The solution to 1/(ln(2))ln|2^x+9|>0.999 is True for all x