What are the solutions to the equation 13x^2+5x+1=0 ?

The solutions to the equation 13x^2+5x+1=0 are x=-5/26+i(3sqrt(3))/(26),x=-5/26-i(3sqrt(3))/(26)

Find the zeros of 13x^2+5x+1=0

The zeros of 13x^2+5x+1=0 are x=-5/26+i(3sqrt(3))/(26),x=-5/26-i(3sqrt(3))/(26)

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13 x^{2} + 5 x + 1 = 0

x = - \frac{5}{26} + i \frac{3 3}{26}, x = - \frac{5}{26} - i \frac{3 3}{26}

Solution steps

13 x^{2} + 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 13 \cdot 1}{2 \cdot 13}

Simplify

5^{2} - 4 \cdot 13 \cdot 1 : 33 i

x_{1, 2} = \frac{- 5 \pm 3 3 i}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- 5 + 3 3 i}{2 \cdot 13}, x_{2} = \frac{- 5 - 3 3 i}{2 \cdot 13}

x = \frac{- 5 + 3 3 i}{2 \cdot 13} : - \frac{5}{26} + i \frac{3 3}{26}

x = \frac{- 5 - 3 3 i}{2 \cdot 13} : - \frac{5}{26} - i \frac{3 3}{26}

The solutions to the quadratic equation are:

x = - \frac{5}{26} + i \frac{3 3}{26}, x = - \frac{5}{26} - i \frac{3 3}{26}

5 x^{2} + 34 x - 7

- x + x^{4}

2 (x + 1)^{2} - 8 = 0

- \frac{π}{2} + \frac{π}{6}

a^{2} + 5 a - 14 = 0

What are the solutions to the equation 13x^2+5x+1=0 ?
The solutions to the equation 13x^2+5x+1=0 are x=-5/26+i(3sqrt(3))/(26),x=-5/26-i(3sqrt(3))/(26)
Find the zeros of 13x^2+5x+1=0
The zeros of 13x^2+5x+1=0 are x=-5/26+i(3sqrt(3))/(26),x=-5/26-i(3sqrt(3))/(26)