What are the solutions to the equation x^2+21=10x ?

The solutions to the equation x^2+21=10x are x=7,x=3

Find the zeros of x^2+21=10x

The zeros of x^2+21=10x are x=7,x=3

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x^{2} + 21 = 10 x

x = 7, x = 3

Solution steps

x^{2} + 21 = 10 x

Move

10 x

to the left side

x^{2} + 21 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 10 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 21 = 4

x_{1, 2} = \frac{- ( - 10 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4}{2 \cdot 1} : 7

x = \frac{- ( - 10 ) - 4}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 7, x = 3

r^{3} + 8 r^{2} + 16 r

\frac{3}{3 - 7 i}

x^{5} + 3^{5}

∣ x - 2 ∣ = ∣ 8 - x ∣

\frac{n}{n ^{2}}

What are the solutions to the equation x^2+21=10x ?
The solutions to the equation x^2+21=10x are x=7,x=3
Find the zeros of x^2+21=10x
The zeros of x^2+21=10x are x=7,x=3