What are the solutions to the equation (5x+1)^2+3=10 ?

The solutions to the equation (5x+1)^2+3=10 are x=(sqrt(7)-1)/5 ,x=(-sqrt(7)-1)/5

Find the zeros of (5x+1)^2+3=10

The zeros of (5x+1)^2+3=10 are x=(sqrt(7)-1)/5 ,x=(-sqrt(7)-1)/5

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(5 x + 1)^{2} + 3 = 10

x = \frac{7 - 1}{5}, x = \frac{- 7 - 1}{5}

Decimal Notation

x = 0.32915 \dots, x = - 0.72915 \dots

Solution steps

(5 x + 1)^{2} + 3 = 10

Move

3

to the right side

(5 x + 1)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 1 = 7 : x = \frac{7 - 1}{5}

Solve

5 x + 1 = - 7 : x = \frac{- 7 - 1}{5}

The solutions to the quadratic equation are:

x = \frac{7 - 1}{5}, x = \frac{- 7 - 1}{5}

2 (x + 3) (x - 2)^{3} + (x + 3)^{2} \cdot 3 (x - 2)^{2}

\frac{8 ( 3 ) - 3 ( 4 ) ^{2}}{3 ( 3 ) ^{2} - 8 ( 4 )}

722

7 a^{2} - 11 a + 4

8 x - x^{2} - 7

What are the solutions to the equation (5x+1)^2+3=10 ?
The solutions to the equation (5x+1)^2+3=10 are x=(sqrt(7)-1)/5 ,x=(-sqrt(7)-1)/5
Find the zeros of (5x+1)^2+3=10
The zeros of (5x+1)^2+3=10 are x=(sqrt(7)-1)/5 ,x=(-sqrt(7)-1)/5