What are the solutions to the equation 9x^2+6x-4=0 ?

The solutions to the equation 9x^2+6x-4=0 are x=(-1+sqrt(5))/3 ,x=-(1+sqrt(5))/3

Find the zeros of 9x^2+6x-4=0

The zeros of 9x^2+6x-4=0 are x=(-1+sqrt(5))/3 ,x=-(1+sqrt(5))/3

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9 x^{2} + 6 x - 4 = 0

x = \frac{- 1 + 5}{3}, x = - \frac{1 + 5}{3}

Decimal Notation

x = 0.41202 \dots, x = - 1.07868 \dots

Solution steps

9 x^{2} + 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 ( - 4 )}{2 \cdot 9}

6^{2} - 4 \cdot 9 (- 4) = 65

x_{1, 2} = \frac{- 6 \pm 6 5}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 6 5}{2 \cdot 9}, x_{2} = \frac{- 6 - 6 5}{2 \cdot 9}

x = \frac{- 6 + 6 5}{2 \cdot 9} : \frac{- 1 + 5}{3}

x = \frac{- 6 - 6 5}{2 \cdot 9} : - \frac{1 + 5}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 5}{3}, x = - \frac{1 + 5}{3}

\frac{d ^{2} e ^{3} f ^{5}}{e ^{6} f ^{7} g ^{8}}

2 x^{2} = 10 x + 3

(\frac{a + b}{a - b})^{2}

7 x^{2} = - 28 x

c - \frac{5}{8} = \frac{1}{2}

What are the solutions to the equation 9x^2+6x-4=0 ?
The solutions to the equation 9x^2+6x-4=0 are x=(-1+sqrt(5))/3 ,x=-(1+sqrt(5))/3
Find the zeros of 9x^2+6x-4=0
The zeros of 9x^2+6x-4=0 are x=(-1+sqrt(5))/3 ,x=-(1+sqrt(5))/3