What are the solutions to the equation -20v=4v^2+25 ?

The solutions to the equation -20v=4v^2+25 are v=-5/2

Find the zeros of -20v=4v^2+25

The zeros of -20v=4v^2+25 are v=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 20 v = 4 v^{2} + 25

v = - \frac{5}{2}

Decimal Notation

v = - 2.5

Solution steps

- 20 v = 4 v^{2} + 25

Switch sides

4 v^{2} + 25 = - 20 v

Move

20 v

to the left side

4 v^{2} + 25 + 20 v = 0

Write in the standard form

a x^{2} + b x + c = 0

4 v^{2} + 20 v + 25 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 25 = 0

v_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 4}

v = \frac{- 20}{2 \cdot 4}

\frac{- 20}{2 \cdot 4} = - \frac{5}{2}

v = - \frac{5}{2}

The solution to the quadratic equation is:

v = - \frac{5}{2}

1 \geq 2 x^{2} + x

16 + 9

7 x^{2} - x = 7

1 - \frac{1}{1 + a}

10 + 3 k < 1

What are the solutions to the equation -20v=4v^2+25 ?
The solutions to the equation -20v=4v^2+25 are v=-5/2
Find the zeros of -20v=4v^2+25
The zeros of -20v=4v^2+25 are v=-5/2