What are the solutions to the equation (x+6)(-x+1)=0 ?

The solutions to the equation (x+6)(-x+1)=0 are x=-6,x=1

Find the zeros of (x+6)(-x+1)=0

The zeros of (x+6)(-x+1)=0 are x=-6,x=1

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(x + 6) (- x + 1) = 0

x = - 6, x = 1

Solution steps

(x + 6) (- x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 6 = 0 or - x + 1 = 0

Solve

x + 6 = 0 : x = - 6

Solve

- x + 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = - 6, x = 1

\frac{5}{11}

v^{3} - 1

i^{33}

x^{4} - 5 x^{3} + x^{2} - 5 x

\frac{x - 5}{x + 4} \geq 0

What are the solutions to the equation (x+6)(-x+1)=0 ?
The solutions to the equation (x+6)(-x+1)=0 are x=-6,x=1
Find the zeros of (x+6)(-x+1)=0
The zeros of (x+6)(-x+1)=0 are x=-6,x=1