What is -10<= 4x+12<= 8 ?

The solution to -10<= 4x+12<= 8 is -11/2 <= x<=-1

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-10<= 4x+12<= 8

- 10 \leq 4 x + 12 \leq 8

- \frac{11}{2} \leq x \leq - 1

Interval Notation

[- \frac{11}{2}, - 1]

Decimal Notation

- 5.5 \leq x \leq - 1

Solution steps

- 10 \leq 4 x + 12 \leq 8

a \leq u \leq b

then

a \leq u and u \leq b

- 10 \leq 4 x + 12 and 4 x + 12 \leq 8

- 10 \leq 4 x + 12 : x \geq - \frac{11}{2}

4 x + 12 \leq 8 : x \leq - 1

Combine the intervals

x \geq - \frac{11}{2} and x \leq - 1

Merge Overlapping Intervals

- \frac{11}{2} \leq x \leq - 1

(\frac{x ^{3} y ^{- 2}}{x ^{- 3} y ^{2}})^{- 2}

\frac{2}{\frac{π}{2}}

2 - 3 x > 0

lo g_{16} (\frac{1}{4})

\frac{2}{\frac{1}{4}}