What are the solutions to the equation (2x+1)(x-1/2)=0 ?

The solutions to the equation (2x+1)(x-1/2)=0 are x=-1/2 ,x= 1/2

Find the zeros of (2x+1)(x-1/2)=0

The zeros of (2x+1)(x-1/2)=0 are x=-1/2 ,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x + 1) (x - \frac{1}{2}) = 0

x = - \frac{1}{2}, x = \frac{1}{2}

Decimal Notation

x = - 0.5, x = 0.5

Solution steps

(2 x + 1) (x - \frac{1}{2}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or x - \frac{1}{2} = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x - \frac{1}{2} = 0 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = \frac{1}{2}

6 - ∣ x + 1 ∣ - 2 x = 5

b^{\frac{3}{2}}

- x^{2} + 3 x + 4

6 a^{2} + 13 ab - 5 b^{2}

(\frac{1}{9})^{2} \cdot (- 3)^{3}

What are the solutions to the equation (2x+1)(x-1/2)=0 ?
The solutions to the equation (2x+1)(x-1/2)=0 are x=-1/2 ,x= 1/2
Find the zeros of (2x+1)(x-1/2)=0
The zeros of (2x+1)(x-1/2)=0 are x=-1/2 ,x= 1/2