What is ((1+i)^2)/(1-i) ?

The solution to ((1+i)^2)/(1-i) is -1+i

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simplify ((1+i)^2)/(1-i)

simplify

\frac{( 1 + i ) ^{2}}{1 - i}

- 1 + i

Solution steps

\frac{( 1 + i ) ^{2}}{1 - i}

Multiply by the conjugate

\frac{1 + i}{1 + i}

= \frac{( 1 + i ) ^{2} ( 1 + i )}{( 1 - i ) ( 1 + i )}

Simplify

\frac{( 1 + i ) ^{2} ( 1 + i )}{( 1 - i ) ( 1 + i )} : \frac{2 i - 2}{2}

= \frac{2 i - 2}{2}

Rewrite in standard complex form:

- 1 + i

= - 1 + i

7 x = 78

\frac{2}{3} \cdot \frac{5}{2}

a^{2} b^{2} - 100

\frac{3}{2 6}

x^{2} - 7 - \frac{81}{10 ( x + 5 )} + \frac{81}{10 ( x - 5 )} \geq 0