What are the solutions to the equation (m-1/2)^2=5 ?

The solutions to the equation (m-1/2)^2=5 are m=sqrt(5)+1/2 ,m=-sqrt(5)+1/2

Find the zeros of (m-1/2)^2=5

The zeros of (m-1/2)^2=5 are m=sqrt(5)+1/2 ,m=-sqrt(5)+1/2

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(m - \frac{1}{2})^{2} = 5

m = 5 + \frac{1}{2}, m = - 5 + \frac{1}{2}

Decimal Notation

m = 2.73606 \dots, m = - 1.73606 \dots

Solution steps

(m - \frac{1}{2})^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

m - \frac{1}{2} = 5 : m = 5 + \frac{1}{2}

Solve

m - \frac{1}{2} = - 5 : m = - 5 + \frac{1}{2}

The solutions to the quadratic equation are:

m = 5 + \frac{1}{2}, m = - 5 + \frac{1}{2}

- 5 + \frac{63}{9}

4 x^{2} - 12

3 y^{2} + 8 y + 5

\frac{7}{x} > 2

x^{2} - 1 x - 20

What are the solutions to the equation (m-1/2)^2=5 ?
The solutions to the equation (m-1/2)^2=5 are m=sqrt(5)+1/2 ,m=-sqrt(5)+1/2
Find the zeros of (m-1/2)^2=5
The zeros of (m-1/2)^2=5 are m=sqrt(5)+1/2 ,m=-sqrt(5)+1/2