en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6x^2+17x-3>= 0

Solution

6 x^{2} + 17 x - 3 \geq 0

Solution

x \leq - 3 or x \geq \frac{1}{6}

+2

Solution steps

6 x^{2} + 17 x - 3 \geq 0

Factor

6 x^{2} + 17 x - 3 : (6 x - 1) (x + 3)

(6 x - 1) (x + 3) \geq 0

Identify the intervals

x \leq - 3 or x \geq \frac{1}{6}

Popular Examples

factor 3x^2+11x+10 factor

3 x^{2} + 11 x + 10

simplify 2/3*4^{3/2}simplify

\frac{2}{3} \cdot 4^{\frac{3}{2}}

4 x^{2} - 5 x = x^{2} + 28

3m^2+13=m^2+397

3 m^{2} + 13 = m^{2} + 397

factor 2x^2y-5x^2-2y+5 factor

2 x^{2} y - 5 x^{2} - 2 y + 5

Frequently Asked Questions (FAQ)

What is 6x^2+17x-3>= 0 ?
The solution to 6x^2+17x-3>= 0 is x<=-3\lor x>= 1/6