What are the solutions to the equation (x^2+x^2)/4 =1 ?

The solutions to the equation (x^2+x^2)/4 =1 are x=sqrt(2),x=-sqrt(2)

Find the zeros of (x^2+x^2)/4 =1

The zeros of (x^2+x^2)/4 =1 are x=sqrt(2),x=-sqrt(2)

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\frac{x ^{2} + x ^{2}}{4} = 1

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

\frac{x ^{2} + x ^{2}}{4} = 1

Multiply both sides by

4

2 x^{2} = 4

Divide both sides by

2

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

3 x - 5 = 2 x - 17

360 - 4 q = 180

3 > ∣ - 5 + 6 x ∣

\frac{1}{2} - \frac{2}{2}

a^{2} - 14 ab + 24 b^{2}

What are the solutions to the equation (x^2+x^2)/4 =1 ?
The solutions to the equation (x^2+x^2)/4 =1 are x=sqrt(2),x=-sqrt(2)
Find the zeros of (x^2+x^2)/4 =1
The zeros of (x^2+x^2)/4 =1 are x=sqrt(2),x=-sqrt(2)