What are the solutions to the equation 4(x+8)^2-40=-36 ?

The solutions to the equation 4(x+8)^2-40=-36 are x=-7,x=-9

Find the zeros of 4(x+8)^2-40=-36

The zeros of 4(x+8)^2-40=-36 are x=-7,x=-9

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4 (x + 8)^{2} - 40 = - 36

x = - 7, x = - 9

Solution steps

4 (x + 8)^{2} - 40 = - 36

Move

40

to the right side

4 (x + 8)^{2} = 4

Divide both sides by

4

(x + 8)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 8 = 1 : x = - 7

Solve

x + 8 = - 1 : x = - 9

The solutions to the quadratic equation are:

x = - 7, x = - 9

(r^{2} s)^{5}

35 w^{2} + 47 w - 60

2 (w + 2) - w = 3 (w - 1) + 9

6 - (3 z - 5) = 3 - 4 z

\frac{x ^{- 2} - y ^{- 2}}{x ^{- 1} y ^{- 1}}

What are the solutions to the equation 4(x+8)^2-40=-36 ?
The solutions to the equation 4(x+8)^2-40=-36 are x=-7,x=-9
Find the zeros of 4(x+8)^2-40=-36
The zeros of 4(x+8)^2-40=-36 are x=-7,x=-9