What are the solutions to the equation -8(x)=2x^2+2x-20 ?

The solutions to the equation -8(x)=2x^2+2x-20 are x=(-5+sqrt(65))/2 ,x=-(5+sqrt(65))/2

Find the zeros of -8(x)=2x^2+2x-20

The zeros of -8(x)=2x^2+2x-20 are x=(-5+sqrt(65))/2 ,x=-(5+sqrt(65))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 8 (x) = 2 x^{2} + 2 x - 20

x = \frac{- 5 + 65}{2}, x = - \frac{5 + 65}{2}

Decimal Notation

x = 1.53112 \dots, x = - 6.53112 \dots

Solution steps

- 8 (x) = 2 x^{2} + 2 x - 20

Refine

- 8 x = 2 x^{2} + 2 x - 20

Switch sides

2 x^{2} + 2 x - 20 = - 8 x

Move

8 x

to the left side

2 x^{2} + 10 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 20 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 20) = 265

x_{1, 2} = \frac{- 10 \pm 2 65}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 2 65}{2 \cdot 2}, x_{2} = \frac{- 10 - 2 65}{2 \cdot 2}

x = \frac{- 10 + 2 65}{2 \cdot 2} : \frac{- 5 + 65}{2}

x = \frac{- 10 - 2 65}{2 \cdot 2} : - \frac{5 + 65}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 65}{2}, x = - \frac{5 + 65}{2}

\frac{8}{15} = \frac{m}{11}

\frac{a ^{2}}{a}

- 5 ∣ 4 - x ∣ < - 15

3 x + 10 + 2 x = 50

4 x + 3 = 1

What are the solutions to the equation -8(x)=2x^2+2x-20 ?
The solutions to the equation -8(x)=2x^2+2x-20 are x=(-5+sqrt(65))/2 ,x=-(5+sqrt(65))/2
Find the zeros of -8(x)=2x^2+2x-20
The zeros of -8(x)=2x^2+2x-20 are x=(-5+sqrt(65))/2 ,x=-(5+sqrt(65))/2