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Popular >

x^2+3x-12>0

Solution

x^{2} + 3 x - 12 > 0

Solution

x < \frac{- 57 - 3}{2} or x > \frac{57 - 3}{2}

+2

Solution steps

x^{2} + 3 x - 12 > 0

Complete the square

x^{2} + 3 x - 12 : (x + \frac{3}{2})^{2} - \frac{57}{4}

(x + \frac{3}{2})^{2} - \frac{57}{4} > 0

Move

\frac{57}{4}

to the right side

(x + \frac{3}{2})^{2} > \frac{57}{4}

For

u^{n} > a

, if

n

is even then

x + \frac{3}{2} < - \frac{57}{4} or x + \frac{3}{2} > \frac{57}{4}

x + \frac{3}{2} < - \frac{57}{4} : x < \frac{- 57 - 3}{2}

x + \frac{3}{2} > \frac{57}{4} : x > \frac{57 - 3}{2}

Combine the intervals

x < \frac{- 57 - 3}{2} or x > \frac{57 - 3}{2}

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64 c z^{3} + 27 c x^{3}

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(\frac{3}{2})^{- 5}

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1 + (- \frac{1}{2})

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\frac{8}{2}

Frequently Asked Questions (FAQ)

What is x^2+3x-12>0 ?
The solution to x^2+3x-12>0 is x<(-sqrt(57)-3)/2 \lor x>(sqrt(57)-3)/2