What are the solutions to the equation 0=3x^2-24x+36 ?

The solutions to the equation 0=3x^2-24x+36 are x=6,x=2

Find the zeros of 0=3x^2-24x+36

The zeros of 0=3x^2-24x+36 are x=6,x=2

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0 = 3 x^{2} - 24 x + 36

x = 6, x = 2

Solution steps

0 = 3 x^{2} - 24 x + 36

Switch sides

3 x^{2} - 24 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 36}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 \cdot 36 = 12

x_{1, 2} = \frac{- ( - 24 ) \pm 12}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 12}{2 \cdot 3}

x = \frac{- ( - 24 ) + 12}{2 \cdot 3} : 6

x = \frac{- ( - 24 ) - 12}{2 \cdot 3} : 2

The solutions to the quadratic equation are:

x = 6, x = 2

(5 x + 3)^{2} = 5 x + 3

3 + \frac{1}{2}

∣ 2 x - 5 ∣ \leq 3

\frac{n}{8} = \frac{n}{7} - 1

x^{2} - 10 x - 11

What are the solutions to the equation 0=3x^2-24x+36 ?
The solutions to the equation 0=3x^2-24x+36 are x=6,x=2
Find the zeros of 0=3x^2-24x+36
The zeros of 0=3x^2-24x+36 are x=6,x=2