What are the solutions to the equation 3/4 = n/(12)n ?

The solutions to the equation 3/4 = n/(12)n are n=3,n=-3

Find the zeros of 3/4 = n/(12)n

The zeros of 3/4 = n/(12)n are n=3,n=-3

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\frac{3}{4} = \frac{n}{12} n

n = 3, n = - 3

Solution steps

\frac{3}{4} = \frac{n}{12} n

Switch sides

\frac{n}{12} n = \frac{3}{4}

Simplify

\frac{n ^{2}}{12} = \frac{3}{4}

Multiply both sides by

12

\frac{12 n ^{2}}{12} = \frac{3 \cdot 12}{4}

n^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 9, n = - 9

9 = 3

- 9 = - 3

n = 3, n = - 3

\frac{1}{2} f - 4 = 1

- \frac{23}{2} (\frac{1}{100 0 ^{2}}) + \frac{23}{2}

6

x^{2} (x + 7) (x - 6) > 0

\frac{- 32 + 8 i}{5 + 3 i}

What are the solutions to the equation 3/4 = n/(12)n ?
The solutions to the equation 3/4 = n/(12)n are n=3,n=-3
Find the zeros of 3/4 = n/(12)n
The zeros of 3/4 = n/(12)n are n=3,n=-3