What are the solutions to the equation x^2-2x+63=0 ?

The solutions to the equation x^2-2x+63=0 are x=1+sqrt(62)i,x=1-sqrt(62)i

Find the zeros of x^2-2x+63=0

The zeros of x^2-2x+63=0 are x=1+sqrt(62)i,x=1-sqrt(62)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 2 x + 63 = 0

x = 1 + 62 i, x = 1 - 62 i

Solution steps

x^{2} - 2 x + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 63}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 63 : 262 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 62 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 62 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 62 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 62 i}{2 \cdot 1} : 1 + 62 i

x = \frac{- ( - 2 ) - 2 62 i}{2 \cdot 1} : 1 - 62 i

The solutions to the quadratic equation are:

x = 1 + 62 i, x = 1 - 62 i

0 = 0.1017 x + 0.0621

\frac{π}{2} - 2 π

\frac{x - 2}{x - 4} \leq 0

7 x + 9 = 8 x + 2

0 + 1

What are the solutions to the equation x^2-2x+63=0 ?
The solutions to the equation x^2-2x+63=0 are x=1+sqrt(62)i,x=1-sqrt(62)i
Find the zeros of x^2-2x+63=0
The zeros of x^2-2x+63=0 are x=1+sqrt(62)i,x=1-sqrt(62)i