What are the solutions to the equation 4x^2+9x-1=0 ?

The solutions to the equation 4x^2+9x-1=0 are x=(-9+sqrt(97))/8 ,x=(-9-sqrt(97))/8

Find the zeros of 4x^2+9x-1=0

The zeros of 4x^2+9x-1=0 are x=(-9+sqrt(97))/8 ,x=(-9-sqrt(97))/8

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4 x^{2} + 9 x - 1 = 0

x = \frac{- 9 + 97}{8}, x = \frac{- 9 - 97}{8}

Decimal Notation

x = 0.10610 \dots, x = - 2.35610 \dots

Solution steps

4 x^{2} + 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

9^{2} - 4 \cdot 4 (- 1) = 97

x_{1, 2} = \frac{- 9 \pm 97}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 97}{2 \cdot 4}, x_{2} = \frac{- 9 - 97}{2 \cdot 4}

x = \frac{- 9 + 97}{2 \cdot 4} : \frac{- 9 + 97}{8}

x = \frac{- 9 - 97}{2 \cdot 4} : \frac{- 9 - 97}{8}

The solutions to the quadratic equation are:

x = \frac{- 9 + 97}{8}, x = \frac{- 9 - 97}{8}

- \frac{5}{3} \cdot (- \frac{1}{7})

\frac{1}{1 + e ^{- 0.5}}

5 (x + 7) = 50

3 x^{3} y^{2} - 9 x^{2} y^{4} + 3 x y^{3}

8 x + 3 = 11

What are the solutions to the equation 4x^2+9x-1=0 ?
The solutions to the equation 4x^2+9x-1=0 are x=(-9+sqrt(97))/8 ,x=(-9-sqrt(97))/8
Find the zeros of 4x^2+9x-1=0
The zeros of 4x^2+9x-1=0 are x=(-9+sqrt(97))/8 ,x=(-9-sqrt(97))/8