What are the solutions to the equation -2v(v+1)=0 ?

The solutions to the equation -2v(v+1)=0 are v=0,v=-1

Find the zeros of -2v(v+1)=0

The zeros of -2v(v+1)=0 are v=0,v=-1

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- 2 v (v + 1) = 0

v = 0, v = - 1

Solution steps

- 2 v (v + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

v = 0 or v + 1 = 0

Solve

v + 1 = 0 : v = - 1

The solutions to the quadratic equation are:

v = 0, v = - 1

(\frac{1}{2})^{0}

6 ∣ u + 5 ∣ - 7 \leq - 37

3 x^{2} y^{3} - 9 x^{3} y^{2}

I n (x^{2})

\frac{( x + 7 )}{x - 2} \geq 0

What are the solutions to the equation -2v(v+1)=0 ?
The solutions to the equation -2v(v+1)=0 are v=0,v=-1
Find the zeros of -2v(v+1)=0
The zeros of -2v(v+1)=0 are v=0,v=-1