What are the solutions to the equation 5x^2-20x+15=0 ?

The solutions to the equation 5x^2-20x+15=0 are x=3,x=1

Find the zeros of 5x^2-20x+15=0

The zeros of 5x^2-20x+15=0 are x=3,x=1

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5 x^{2} - 20 x + 15 = 0

x = 3, x = 1

Solution steps

5 x^{2} - 20 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 15}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 \cdot 15 = 10

x_{1, 2} = \frac{- ( - 20 ) \pm 10}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 10}{2 \cdot 5}, x_{2} = \frac{- ( - 20 ) - 10}{2 \cdot 5}

x = \frac{- ( - 20 ) + 10}{2 \cdot 5} : 3

x = \frac{- ( - 20 ) - 10}{2 \cdot 5} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

\frac{2 ^{4 m}}{16}

3 - \frac{2}{5}

- 2 < 7 x - 13 \leq 15

6 m^{2} - mn - n^{2}

\frac{3 ( 9 g + 4 )}{4} = 16.5

What are the solutions to the equation 5x^2-20x+15=0 ?
The solutions to the equation 5x^2-20x+15=0 are x=3,x=1
Find the zeros of 5x^2-20x+15=0
The zeros of 5x^2-20x+15=0 are x=3,x=1