What are the solutions to the equation 0=x^2-4x+3 ?

The solutions to the equation 0=x^2-4x+3 are x=3,x=1

Find the zeros of 0=x^2-4x+3

The zeros of 0=x^2-4x+3 are x=3,x=1

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0 = x^{2} - 4 x + 3

x = 3, x = 1

Solution steps

0 = x^{2} - 4 x + 3

Switch sides

x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2}{2 \cdot 1} : 3

x = \frac{- ( - 4 ) - 2}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

\frac{10 \cdot 8.2}{17.5}

0.1 \cdot 100

\frac{( a ^{(3)} )}{( ( a ^{(3)} b ) ^{(2)} )}^{(2)}

4 x \cdot 9 x^{\frac{1}{2}}

3 w^{2} - 6 w + 2 = 0

What are the solutions to the equation 0=x^2-4x+3 ?
The solutions to the equation 0=x^2-4x+3 are x=3,x=1
Find the zeros of 0=x^2-4x+3
The zeros of 0=x^2-4x+3 are x=3,x=1