What are the solutions to the equation 2x^2+3x+4=0 ?

The solutions to the equation 2x^2+3x+4=0 are x=-3/4+i(sqrt(23))/4 ,x=-3/4-i(sqrt(23))/4

Find the zeros of 2x^2+3x+4=0

The zeros of 2x^2+3x+4=0 are x=-3/4+i(sqrt(23))/4 ,x=-3/4-i(sqrt(23))/4

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2 x^{2} + 3 x + 4 = 0

x = - \frac{3}{4} + i \frac{23}{4}, x = - \frac{3}{4} - i \frac{23}{4}

Solution steps

2 x^{2} + 3 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

Simplify

3^{2} - 4 \cdot 2 \cdot 4 : 23 i

x_{1, 2} = \frac{- 3 \pm 23 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 23 i}{2 \cdot 2}, x_{2} = \frac{- 3 - 23 i}{2 \cdot 2}

x = \frac{- 3 + 23 i}{2 \cdot 2} : - \frac{3}{4} + i \frac{23}{4}

x = \frac{- 3 - 23 i}{2 \cdot 2} : - \frac{3}{4} - i \frac{23}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{4} + i \frac{23}{4}, x = - \frac{3}{4} - i \frac{23}{4}

\frac{- 2}{5 - i}

\frac{5}{8} - \frac{5}{6}

(\frac{3 w x ^{- 4} y ^{5}}{w ^{- 3}})^{- 4}

- 2 < x < 3

1 + \frac{0.06}{365}

What are the solutions to the equation 2x^2+3x+4=0 ?
The solutions to the equation 2x^2+3x+4=0 are x=-3/4+i(sqrt(23))/4 ,x=-3/4-i(sqrt(23))/4
Find the zeros of 2x^2+3x+4=0
The zeros of 2x^2+3x+4=0 are x=-3/4+i(sqrt(23))/4 ,x=-3/4-i(sqrt(23))/4