What are the solutions to the equation (z+3)^2=-19 ?

The solutions to the equation (z+3)^2=-19 are z=sqrt(19)i-3,z=-sqrt(19)i-3

Find the zeros of (z+3)^2=-19

The zeros of (z+3)^2=-19 are z=sqrt(19)i-3,z=-sqrt(19)i-3

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(z + 3)^{2} = - 19

z = 19 i - 3, z = - 19 i - 3

Solution steps

(z + 3)^{2} = - 19

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 3 = - 19 : z = 19 i - 3

Solve

z + 3 = - - 19 : z = - 19 i - 3

The solutions to the quadratic equation are:

z = 19 i - 3, z = - 19 i - 3

\frac{5 ^{0} e ^{- 5}}{0 !}

20 - 80

\frac{5 !}{5 ! ( 5 - 5 ) !}

28 - 550

1000 = 800 (1 + \frac{x}{100})

What are the solutions to the equation (z+3)^2=-19 ?
The solutions to the equation (z+3)^2=-19 are z=sqrt(19)i-3,z=-sqrt(19)i-3
Find the zeros of (z+3)^2=-19
The zeros of (z+3)^2=-19 are z=sqrt(19)i-3,z=-sqrt(19)i-3