What are the solutions to the equation 12x-6x^2=-20 ?

The solutions to the equation 12x-6x^2=-20 are x=-(-3+sqrt(39))/3 ,x=(3+sqrt(39))/3

Find the zeros of 12x-6x^2=-20

The zeros of 12x-6x^2=-20 are x=-(-3+sqrt(39))/3 ,x=(3+sqrt(39))/3

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12 x - 6 x^{2} = - 20

x = - \frac{- 3 + 39}{3}, x = \frac{3 + 39}{3}

Decimal Notation

x = - 1.08166 \dots, x = 3.08166 \dots

Solution steps

12 x - 6 x^{2} = - 20

Move

20

to the left side

12 x - 6 x^{2} + 20 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 6 x^{2} + 12 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 6 ) \cdot 20}{2 ( - 6 )}

1 2^{2} - 4 (- 6) \cdot 20 = 439

x_{1, 2} = \frac{- 12 \pm 4 39}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 12 + 4 39}{2 ( - 6 )}, x_{2} = \frac{- 12 - 4 39}{2 ( - 6 )}

x = \frac{- 12 + 4 39}{2 ( - 6 )} : - \frac{- 3 + 39}{3}

x = \frac{- 12 - 4 39}{2 ( - 6 )} : \frac{3 + 39}{3}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 39}{3}, x = \frac{3 + 39}{3}

3 x (x - 3) = 5 x^{2} - 10 x

- x^{2} + 49

8^{\frac{7}{4}} \cdot 2^{\frac{7}{4}}

x^{2} - 5 x + 10 > 0

2 g^{2} + 7 g + 5

What are the solutions to the equation 12x-6x^2=-20 ?
The solutions to the equation 12x-6x^2=-20 are x=-(-3+sqrt(39))/3 ,x=(3+sqrt(39))/3
Find the zeros of 12x-6x^2=-20
The zeros of 12x-6x^2=-20 are x=-(-3+sqrt(39))/3 ,x=(3+sqrt(39))/3