What are the solutions to the equation 4x^2+x-5=0 ?

The solutions to the equation 4x^2+x-5=0 are x=1,x=-5/4

Find the zeros of 4x^2+x-5=0

The zeros of 4x^2+x-5=0 are x=1,x=-5/4

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4 x^{2} + x - 5 = 0

x = 1, x = - \frac{5}{4}

Decimal Notation

x = 1, x = - 1.25

Solution steps

4 x^{2} + x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 5) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 4}, x_{2} = \frac{- 1 - 9}{2 \cdot 4}

x = \frac{- 1 + 9}{2 \cdot 4} : 1

x = \frac{- 1 - 9}{2 \cdot 4} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = 1, x = - \frac{5}{4}

(15625 x)^{\frac{1}{6}}

(x + 4)^{2} (x + 1) (x + 7) \leq 0

\frac{1}{3} + \frac{4}{5}

(\frac{2}{5 n ^{9}})^{2}

8 x + 6 = 9 x - 30

What are the solutions to the equation 4x^2+x-5=0 ?
The solutions to the equation 4x^2+x-5=0 are x=1,x=-5/4
Find the zeros of 4x^2+x-5=0
The zeros of 4x^2+x-5=0 are x=1,x=-5/4