What are the solutions to the equation 2x^2-3=-3 ?

The solutions to the equation 2x^2-3=-3 are x=0

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2x^2-3=-3

2 x^{2} - 3 = - 3

x = 0

Solution steps

2 x^{2} - 3 = - 3

Move

3

to the right side

2 x^{2} = 0

Divide both sides by

2

x = 0

13.6 \cdot 0.64 + 1.28 \cdot 7.2 + 7.2 \cdot 0.72 + 0.36 \cdot 13.6

5 x - (x - 2) \geq 2 x - 4 (x - 8)

\frac{5}{8} \cdot \frac{4}{7}

22 x^{4} y^{5} z^{5} + 47 x^{6} y^{3} z^{3}

\frac{3 x - 4}{- 2} > \frac{- 2 x}{5}

What are the solutions to the equation 2x^2-3=-3 ?
The solutions to the equation 2x^2-3=-3 are x=0
Find the zeros of 2x^2-3=-3
The zeros of 2x^2-3=-3 are x=0