What are the solutions to the equation 4x^2-32x=-28 ?

The solutions to the equation 4x^2-32x=-28 are x=7,x=1

Find the zeros of 4x^2-32x=-28

The zeros of 4x^2-32x=-28 are x=7,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 32 x = - 28

x = 7, x = 1

Solution steps

4 x^{2} - 32 x = - 28

Move

28

to the left side

4 x^{2} - 32 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 4 \cdot 28}{2 \cdot 4}

(- 32)^{2} - 4 \cdot 4 \cdot 28 = 24

x_{1, 2} = \frac{- ( - 32 ) \pm 24}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 32 ) + 24}{2 \cdot 4}, x_{2} = \frac{- ( - 32 ) - 24}{2 \cdot 4}

x = \frac{- ( - 32 ) + 24}{2 \cdot 4} : 7

x = \frac{- ( - 32 ) - 24}{2 \cdot 4} : 1

The solutions to the quadratic equation are:

x = 7, x = 1

- 5 \cdot 0

- 15 r = 102

5 + \frac{1}{6}

5 - 3 (\frac{1}{2} x + 2) = - 7

30 < - 3 n

What are the solutions to the equation 4x^2-32x=-28 ?
The solutions to the equation 4x^2-32x=-28 are x=7,x=1
Find the zeros of 4x^2-32x=-28
The zeros of 4x^2-32x=-28 are x=7,x=1