What are the solutions to the equation x^2-12x+85=0 ?

The solutions to the equation x^2-12x+85=0 are x=6+7i,x=6-7i

Find the zeros of x^2-12x+85=0

The zeros of x^2-12x+85=0 are x=6+7i,x=6-7i

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x^{2} - 12 x + 85 = 0

x = 6 + 7 i, x = 6 - 7 i

Solution steps

x^{2} - 12 x + 85 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 85}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot 85 : 14 i

x_{1, 2} = \frac{- ( - 12 ) \pm 14 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 14 i}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 14 i}{2 \cdot 1}

x = \frac{- ( - 12 ) + 14 i}{2 \cdot 1} : 6 + 7 i

x = \frac{- ( - 12 ) - 14 i}{2 \cdot 1} : 6 - 7 i

The solutions to the quadratic equation are:

x = 6 + 7 i, x = 6 - 7 i

15 x^{3} - 25 x^{2} + 75 x - 125

a x - 4 b x + 4 a y - 16 b y

(\frac{2}{3})^{- 0.75}

\frac{3}{5} x = 18

\frac{3 x - 2}{4} = \frac{x}{3} + 1

What are the solutions to the equation x^2-12x+85=0 ?
The solutions to the equation x^2-12x+85=0 are x=6+7i,x=6-7i
Find the zeros of x^2-12x+85=0
The zeros of x^2-12x+85=0 are x=6+7i,x=6-7i