What is (250(2^{-3}))/((-5)^2(8^{-2))} ?

The solution to (250(2^{-3}))/((-5)^2(8^{-2))} is 80

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (250(2^{-3}))/((-5)^2(8^{-2))}

simplify

\frac{250 ( 2 ^{- 3} )}{( - 5 ) ^{2} ( 8 ^{- 2} )}

80

Solution steps

\frac{250 ( 2 ^{- 3} )}{( - 5 ) ^{2} ( 8 ^{- 2} )}

\frac{250 ( 2 ^{- 3} )}{( - 5 ) ^{2} ( 8 ^{- 2} )} = \frac{250 \cdot 2 ^{- 3}}{( - 5 ) ^{2} \cdot 8 ^{- 2}}

= \frac{250 \cdot 2 ^{- 3}}{( - 5 ) ^{2} \cdot 8 ^{- 2}}

Factor the number:

250 = 2 \cdot 125

= \frac{2 \cdot 125 \cdot 2 ^{- 3}}{( - 5 ) ^{2} \cdot 8 ^{- 2}}

Factor

8^{- 2} : 2^{- 6}

= \frac{2 \cdot 125 \cdot 2 ^{- 3}}{( - 5 ) ^{2} \cdot 2 ^{- 6}}

\frac{2}{2 ^{- 6}} = 2^{7}

= \frac{2 ^{7} \cdot 125 \cdot 2 ^{- 3}}{( - 5 ) ^{2}}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{2} = 5^{2}

= \frac{2 ^{7} \cdot 125 \cdot 2 ^{- 3}}{5 ^{2}}

Factor the number:

125 = 5^{3}

= \frac{2 ^{7} \cdot 5 ^{3} \cdot 2 ^{- 3}}{5 ^{2}}

\frac{5 ^{3}}{5 ^{2}} = 5

= 2^{7} \cdot 5 \cdot 2^{- 3}

2^{7} \cdot 5 \cdot 2^{- 3} = 80

= 80

4500 = \frac{( ( 0.00000075 ) \cdot R ^{2} )}{2 ( 8.85 \cdot 1 0 ^{- 12} ) ( 0.35 )}

8 s^{3} - 125 t^{3}

\frac{8 !}{2 ! \cdot 6 !}

\frac{7}{6} \cdot 2

What is (250(2^{-3}))/((-5)^2(8^{-2))} ?
The solution to (250(2^{-3}))/((-5)^2(8^{-2))} is 80