What is factor 12x^2-19x+4 ?

The solution to factor 12x^2-19x+4 is (4x-1)(3x-4)

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factor 12x^2-19x+4

factor

12 x^{2} - 19 x + 4

(4 x - 1) (3 x - 4)

Solution steps

12 x^{2} - 19 x + 4

Break the expression into groups

= (12 x^{2} - 3 x) + (- 16 x + 4)

Factor out

3 x

from

12 x^{2} - 3 x : 3 x (4 x - 1)

Factor out

- 4

from

- 16 x + 4 : - 4 (4 x - 1)

= 3 x (4 x - 1) - 4 (4 x - 1)

Factor out common term

4 x - 1

= (4 x - 1) (3 x - 4)

2 x^{2} - 12 x

4 y^{2} - 9 = 0

\frac{6}{- 1}

(\frac{16 x ^{14}}{81 y ^{18}})^{\frac{1}{2}}

(x - 1) (x + 8) \geq 0