What are the solutions to the equation 3x^2+8x-16=0 ?

The solutions to the equation 3x^2+8x-16=0 are x= 4/3 ,x=-4

Find the zeros of 3x^2+8x-16=0

The zeros of 3x^2+8x-16=0 are x= 4/3 ,x=-4

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3 x^{2} + 8 x - 16 = 0

x = \frac{4}{3}, x = - 4

Decimal Notation

x = 1.33333 \dots, x = - 4

Solution steps

3 x^{2} + 8 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 16) = 16

x_{1, 2} = \frac{- 8 \pm 16}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 16}{2 \cdot 3}, x_{2} = \frac{- 8 - 16}{2 \cdot 3}

x = \frac{- 8 + 16}{2 \cdot 3} : \frac{4}{3}

x = \frac{- 8 - 16}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 4

x + 2 < 2 x - 3 \leq x + 1

12 x^{2} + x - 35

e^{- \frac{1}{4}}

\frac{x}{[ - 4 ]} = - 12

(\frac{4}{25})^{\frac{1}{2}}

What are the solutions to the equation 3x^2+8x-16=0 ?
The solutions to the equation 3x^2+8x-16=0 are x= 4/3 ,x=-4
Find the zeros of 3x^2+8x-16=0
The zeros of 3x^2+8x-16=0 are x= 4/3 ,x=-4