What is 6(x^2+1)-(2x-4)(3x+2)<3(5x+21) ?

The solution to 6(x^2+1)-(2x-4)(3x+2) -7

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6(x^2+1)-(2x-4)(3x+2)<3(5x+21)

6 (x^{2} + 1) - (2 x - 4) (3 x + 2) < 3 (5 x + 21)

x > - 7

Interval Notation

(- 7, \infty)

Solution steps

6 (x^{2} + 1) - (2 x - 4) (3 x + 2) < 3 (5 x + 21)

Rewrite in standard form

- x - 7 < 0

Move

7

to the right side

- x < 7

Multiply both sides by

- 1

x > - 7

\frac{3 ( x - 4 )}{2} + \frac{5 ( 2 x + 1 )}{3} = \frac{2 x}{4}

x^{3} y^{3} + 512

50 x - 24 \geq 276

\frac{3 - 10 i}{- 5 i}

27 c^{2} + 108 c + 108 = 0

What is 6(x^2+1)-(2x-4)(3x+2)<3(5x+21) ?
The solution to 6(x^2+1)-(2x-4)(3x+2)<3(5x+21) is x>-7