What are the solutions to the equation 4w^2-28w=0 ?

The solutions to the equation 4w^2-28w=0 are w=7,w=0

Find the zeros of 4w^2-28w=0

The zeros of 4w^2-28w=0 are w=7,w=0

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4 w^{2} - 28 w = 0

w = 7, w = 0

Solution steps

4 w^{2} - 28 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 28)^{2} - 4 \cdot 4 \cdot 0 = 28

w_{1, 2} = \frac{- ( - 28 ) \pm 28}{2 \cdot 4}

Separate the solutions

w_{1} = \frac{- ( - 28 ) + 28}{2 \cdot 4}, w_{2} = \frac{- ( - 28 ) - 28}{2 \cdot 4}

w = \frac{- ( - 28 ) + 28}{2 \cdot 4} : 7

w = \frac{- ( - 28 ) - 28}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

w = 7, w = 0

64 a^{2} - 9

- 3 x^{2} - 2 x + 16

5 x - 1 = 26

5 x^{2} - 11 x - 3 = 0

3 x - 2 = 3

What are the solutions to the equation 4w^2-28w=0 ?
The solutions to the equation 4w^2-28w=0 are w=7,w=0
Find the zeros of 4w^2-28w=0
The zeros of 4w^2-28w=0 are w=7,w=0