What are the solutions to the equation 10u^2+17u+3=0 ?

The solutions to the equation 10u^2+17u+3=0 are u=-1/5 ,u=-3/2

Find the zeros of 10u^2+17u+3=0

The zeros of 10u^2+17u+3=0 are u=-1/5 ,u=-3/2

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10 u^{2} + 17 u + 3 = 0

u = - \frac{1}{5}, u = - \frac{3}{2}

Decimal Notation

u = - 0.2, u = - 1.5

Solution steps

10 u^{2} + 17 u + 3 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 10 \cdot 3}{2 \cdot 10}

1 7^{2} - 4 \cdot 10 \cdot 3 = 13

u_{1, 2} = \frac{- 17 \pm 13}{2 \cdot 10}

Separate the solutions

u_{1} = \frac{- 17 + 13}{2 \cdot 10}, u_{2} = \frac{- 17 - 13}{2 \cdot 10}

u = \frac{- 17 + 13}{2 \cdot 10} : - \frac{1}{5}

u = \frac{- 17 - 13}{2 \cdot 10} : - \frac{3}{2}

The solutions to the quadratic equation are:

u = - \frac{1}{5}, u = - \frac{3}{2}

\frac{7}{4} - \frac{2}{3}

14 + \frac{x}{2} = 3

x + \frac{2}{3} + \frac{1}{3} = 1

\frac{x + 3}{x + 2} < 0

ln (\frac{1}{e ^{- 1}})

What are the solutions to the equation 10u^2+17u+3=0 ?
The solutions to the equation 10u^2+17u+3=0 are u=-1/5 ,u=-3/2
Find the zeros of 10u^2+17u+3=0
The zeros of 10u^2+17u+3=0 are u=-1/5 ,u=-3/2