What are the solutions to the equation 16t^2-224=0 ?

The solutions to the equation 16t^2-224=0 are t=sqrt(14),t=-sqrt(14)

Find the zeros of 16t^2-224=0

The zeros of 16t^2-224=0 are t=sqrt(14),t=-sqrt(14)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 t^{2} - 224 = 0

t = 14, t = - 14

Decimal Notation

t = 3.74165 \dots, t = - 3.74165 \dots

Solution steps

16 t^{2} - 224 = 0

Move

224

to the right side

16 t^{2} = 224

Divide both sides by

16

t^{2} = 14

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 14, t = - 14

4 r^{- 3} \cdot 2 r^{2}

z^{2} - 3 z - 40 = 0

- 5 a + 6 > 11

(x + 9) 4 - 64 (x + 9) 2 = 0

44 t - 16 t^{2} = - \frac{11}{8}

What are the solutions to the equation 16t^2-224=0 ?
The solutions to the equation 16t^2-224=0 are t=sqrt(14),t=-sqrt(14)
Find the zeros of 16t^2-224=0
The zeros of 16t^2-224=0 are t=sqrt(14),t=-sqrt(14)