What are the solutions to the equation 4x^2+9x-4=7x ?

The solutions to the equation 4x^2+9x-4=7x are x=(-1+sqrt(17))/4 ,x=-(1+sqrt(17))/4

Find the zeros of 4x^2+9x-4=7x

The zeros of 4x^2+9x-4=7x are x=(-1+sqrt(17))/4 ,x=-(1+sqrt(17))/4

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4 x^{2} + 9 x - 4 = 7 x

x = \frac{- 1 + 17}{4}, x = - \frac{1 + 17}{4}

Decimal Notation

x = 0.78077 \dots, x = - 1.28077 \dots

Solution steps

4 x^{2} + 9 x - 4 = 7 x

Move

7 x

to the left side

4 x^{2} + 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 ( - 4 )}{2 \cdot 4}

2^{2} - 4 \cdot 4 (- 4) = 217

x_{1, 2} = \frac{- 2 \pm 2 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 2 + 2 17}{2 \cdot 4}, x_{2} = \frac{- 2 - 2 17}{2 \cdot 4}

x = \frac{- 2 + 2 17}{2 \cdot 4} : \frac{- 1 + 17}{4}

x = \frac{- 2 - 2 17}{2 \cdot 4} : - \frac{1 + 17}{4}

The solutions to the quadratic equation are:

x = \frac{- 1 + 17}{4}, x = - \frac{1 + 17}{4}

\frac{( - b ^{2} ) ^{3}}{( - b ^{3} ) ^{2}}

(\frac{3}{10})^{3}

x + x^{2} = 182

- 5 (3 n + 5) = 20

What are the solutions to the equation 4x^2+9x-4=7x ?
The solutions to the equation 4x^2+9x-4=7x are x=(-1+sqrt(17))/4 ,x=-(1+sqrt(17))/4
Find the zeros of 4x^2+9x-4=7x
The zeros of 4x^2+9x-4=7x are x=(-1+sqrt(17))/4 ,x=-(1+sqrt(17))/4