What are the solutions to the equation 25y^2=-16 ?

The solutions to the equation 25y^2=-16 are y= 4/5 i,y=-4/5 i

Find the zeros of 25y^2=-16

The zeros of 25y^2=-16 are y= 4/5 i,y=-4/5 i

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25 y^{2} = - 16

y = \frac{4}{5} i, y = - \frac{4}{5} i

Solution steps

25 y^{2} = - 16

Divide both sides by

25

y^{2} = - \frac{16}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - \frac{16}{25}, y = - - \frac{16}{25}

- \frac{16}{25} = \frac{4}{5} i

- - \frac{16}{25} = - \frac{4}{5} i

y = \frac{4}{5} i, y = - \frac{4}{5} i

x - 8 = 10

(c^{3})^{5} (d^{3})^{0}

2 x + 7 = 5 x + 19

w^{2} - 8 w = 0

\frac{3}{2} \geq x - 2 \geq - \frac{3}{2}

What are the solutions to the equation 25y^2=-16 ?
The solutions to the equation 25y^2=-16 are y= 4/5 i,y=-4/5 i
Find the zeros of 25y^2=-16
The zeros of 25y^2=-16 are y= 4/5 i,y=-4/5 i