What are the solutions to the equation 49y^2+84y+36=0 ?

The solutions to the equation 49y^2+84y+36=0 are y=-6/7

Find the zeros of 49y^2+84y+36=0

The zeros of 49y^2+84y+36=0 are y=-6/7

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49 y^{2} + 84 y + 36 = 0

y = - \frac{6}{7}

Decimal Notation

y = - 0.85714 \dots

Solution steps

49 y^{2} + 84 y + 36 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 84 \pm 8 4 ^{2} - 4 \cdot 49 \cdot 36}{2 \cdot 49}

8 4^{2} - 4 \cdot 49 \cdot 36 = 0

y_{1, 2} = \frac{- 84 \pm 0}{2 \cdot 49}

y = \frac{- 84}{2 \cdot 49}

\frac{- 84}{2 \cdot 49} = - \frac{6}{7}

y = - \frac{6}{7}

The solution to the quadratic equation is:

y = - \frac{6}{7}

(\frac{1}{8})^{- 2}

5 - \frac{8}{9} x \geq \frac{3}{7}

9 x^{2} + 7 x = 0

5 x - 27 = 8

\frac{1}{2} (456.953 - 428.259) \cdot 1 0^{3} \cdot 1.5

What are the solutions to the equation 49y^2+84y+36=0 ?
The solutions to the equation 49y^2+84y+36=0 are y=-6/7
Find the zeros of 49y^2+84y+36=0
The zeros of 49y^2+84y+36=0 are y=-6/7