What are the solutions to the equation 5v^2-16=16v ?

The solutions to the equation 5v^2-16=16v are v=4,v=-4/5

Find the zeros of 5v^2-16=16v

The zeros of 5v^2-16=16v are v=4,v=-4/5

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5 v^{2} - 16 = 16 v

v = 4, v = - \frac{4}{5}

Solution steps

5 v^{2} - 16 = 16 v

Move

16 v

to the left side

5 v^{2} - 16 - 16 v = 0

Write in the standard form

a x^{2} + b x + c = 0

5 v^{2} - 16 v - 16 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 5 ( - 16 )}{2 \cdot 5}

(- 16)^{2} - 4 \cdot 5 (- 16) = 24

v_{1, 2} = \frac{- ( - 16 ) \pm 24}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- ( - 16 ) + 24}{2 \cdot 5}, v_{2} = \frac{- ( - 16 ) - 24}{2 \cdot 5}

v = \frac{- ( - 16 ) + 24}{2 \cdot 5} : 4

v = \frac{- ( - 16 ) - 24}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

v = 4, v = - \frac{4}{5}

3 x^{2} + 6 x = 45

\frac{2}{3} \cdot \frac{2}{3}

lo g_{4} (16) = 4

- 3 x^{2} = - 7 x + 14

- 7 < 3 x + 2 \leq 2

What are the solutions to the equation 5v^2-16=16v ?
The solutions to the equation 5v^2-16=16v are v=4,v=-4/5
Find the zeros of 5v^2-16=16v
The zeros of 5v^2-16=16v are v=4,v=-4/5