What is 6^2+24(2)<= (5x+4x)/2 ?

The solution to 6^2+24(2) = 56/3

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6^2+24(2)<= (5x+4x)/2

6^{2} + 24 (2) \leq \frac{5 x + 4 x}{2}

x \geq \frac{56}{3}

Interval Notation

[\frac{56}{3}, \infty)

Decimal Notation

x \geq 18.66666 \dots

Solution steps

6^{2} + 24 (2) \leq \frac{5 x + 4 x}{2}

Switch sides

\frac{5 x + 4 x}{2} \geq 6^{2} + 24 (2)

Remove parentheses:

(a) = a

\frac{5 x + 4 x}{2} \geq 6^{2} + 24 \cdot 2

Multiply the numbers:

24 \cdot 2 = 48

\frac{5 x + 4 x}{2} \geq 6^{2} + 48

6^{2} = 36

\frac{5 x + 4 x}{2} \geq 36 + 48

Add the numbers:

36 + 48 = 84

\frac{5 x + 4 x}{2} \geq 84

Multiply both sides by

2

9 x \geq 168

Divide both sides by

9

x \geq \frac{56}{3}

x^{4} - 49

5 x^{2} + 4 x - 3 = 0

x - 11 = 16

w^{2} - 9 w + 20

3 x^{2} + 17 x = - 3 x + 7

What is 6^2+24(2)<= (5x+4x)/2 ?
The solution to 6^2+24(2)<= (5x+4x)/2 is x>= 56/3