What are the solutions to the equation 49=(x+2)^2 ?

The solutions to the equation 49=(x+2)^2 are x=5,x=-9

Find the zeros of 49=(x+2)^2

The zeros of 49=(x+2)^2 are x=5,x=-9

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49 = (x + 2)^{2}

x = 5, x = - 9

Solution steps

49 = (x + 2)^{2}

Switch sides

(x + 2)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 49 : x = 5

Solve

x + 2 = - 49 : x = - 9

The solutions to the quadratic equation are:

x = 5, x = - 9

3 + 2 [1 + 2 (2 x - 2)] = 6 (x + 3)

r^{2} - s^{2}

60 \cdot 1 0^{- 6} = 30 \cdot 1 0^{6} (x - 0.4)^{2}

- 98

140000000 = - 66.67 x^{2} + 3133.33 x - 26000

What are the solutions to the equation 49=(x+2)^2 ?
The solutions to the equation 49=(x+2)^2 are x=5,x=-9
Find the zeros of 49=(x+2)^2
The zeros of 49=(x+2)^2 are x=5,x=-9